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1101 | jermar | 1 | /* |
2 | * Copyright (C) 2006 Jakub Jermar |
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3 | * All rights reserved. |
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4 | * |
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5 | * Redistribution and use in source and binary forms, with or without |
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6 | * modification, are permitted provided that the following conditions |
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7 | * are met: |
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8 | * |
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9 | * - Redistributions of source code must retain the above copyright |
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10 | * notice, this list of conditions and the following disclaimer. |
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11 | * - Redistributions in binary form must reproduce the above copyright |
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12 | * notice, this list of conditions and the following disclaimer in the |
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13 | * documentation and/or other materials provided with the distribution. |
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14 | * - The name of the author may not be used to endorse or promote products |
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15 | * derived from this software without specific prior written permission. |
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16 | * |
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17 | * THIS SOFTWARE IS PROVIDED BY THE AUTHOR ``AS IS'' AND ANY EXPRESS OR |
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18 | * IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES |
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19 | * OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE DISCLAIMED. |
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20 | * IN NO EVENT SHALL THE AUTHOR BE LIABLE FOR ANY DIRECT, INDIRECT, |
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21 | * INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT |
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22 | * NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, |
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23 | * DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY |
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24 | * THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT |
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25 | * (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF |
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26 | * THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE. |
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27 | */ |
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28 | |||
29 | /* |
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30 | * This B-tree has the following properties: |
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1164 | jermar | 31 | * - it is a ballanced 3-4-5 tree (i.e. BTREE_M = 5) |
1101 | jermar | 32 | * - values (i.e. pointers to values) are stored only in leaves |
33 | * - leaves are linked in a list |
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1148 | jermar | 34 | * - technically, it is a B+tree (because of the previous properties) |
1101 | jermar | 35 | * |
1134 | jermar | 36 | * Be carefull when using these trees. They need to allocate |
37 | * and deallocate memory for their index nodes and as such |
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38 | * can sleep. |
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1101 | jermar | 39 | */ |
40 | |||
41 | #include <adt/btree.h> |
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42 | #include <adt/list.h> |
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43 | #include <mm/slab.h> |
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44 | #include <debug.h> |
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45 | #include <panic.h> |
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46 | #include <typedefs.h> |
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47 | #include <print.h> |
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48 | |||
1177 | jermar | 49 | static void _btree_insert(btree_t *t, btree_key_t key, void *value, btree_node_t *rsubtree, btree_node_t *node); |
50 | static void _btree_remove(btree_t *t, btree_key_t key, btree_node_t *node); |
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1101 | jermar | 51 | static void node_initialize(btree_node_t *node); |
1177 | jermar | 52 | static void node_insert_key_and_lsubtree(btree_node_t *node, btree_key_t key, void *value, btree_node_t *lsubtree); |
53 | static void node_insert_key_and_rsubtree(btree_node_t *node, btree_key_t key, void *value, btree_node_t *rsubtree); |
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54 | static void node_remove_key_and_lsubtree(btree_node_t *node, btree_key_t key); |
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55 | static void node_remove_key_and_rsubtree(btree_node_t *node, btree_key_t key); |
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56 | static btree_node_t *node_split(btree_node_t *node, btree_key_t key, void *value, btree_node_t *rsubtree, btree_key_t *median); |
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1142 | jermar | 57 | static btree_node_t *node_combine(btree_node_t *node); |
1136 | jermar | 58 | static index_t find_key_by_subtree(btree_node_t *node, btree_node_t *subtree, bool right); |
1142 | jermar | 59 | static void rotate_from_right(btree_node_t *lnode, btree_node_t *rnode, index_t idx); |
60 | static void rotate_from_left(btree_node_t *lnode, btree_node_t *rnode, index_t idx); |
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1177 | jermar | 61 | static bool try_insert_by_rotation_to_left(btree_node_t *node, btree_key_t key, void *value, btree_node_t *rsubtree); |
62 | static bool try_insert_by_rotation_to_right(btree_node_t *node, btree_key_t key, void *value, btree_node_t *rsubtree); |
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1142 | jermar | 63 | static bool try_rotation_from_left(btree_node_t *rnode); |
64 | static bool try_rotation_from_right(btree_node_t *lnode); |
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1101 | jermar | 65 | |
66 | #define ROOT_NODE(n) (!(n)->parent) |
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67 | #define INDEX_NODE(n) ((n)->subtree[0] != NULL) |
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68 | #define LEAF_NODE(n) ((n)->subtree[0] == NULL) |
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69 | |||
1140 | jermar | 70 | #define FILL_FACTOR ((BTREE_M-1)/2) |
71 | |||
1101 | jermar | 72 | #define MEDIAN_LOW_INDEX(n) (((n)->keys-1)/2) |
73 | #define MEDIAN_HIGH_INDEX(n) ((n)->keys/2) |
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74 | #define MEDIAN_LOW(n) ((n)->key[MEDIAN_LOW_INDEX((n))]); |
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75 | #define MEDIAN_HIGH(n) ((n)->key[MEDIAN_HIGH_INDEX((n))]); |
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76 | |||
1164 | jermar | 77 | static slab_cache_t *btree_node_slab; |
78 | |||
79 | /** Initialize B-trees. */ |
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80 | void btree_init(void) |
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81 | { |
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82 | btree_node_slab = slab_cache_create("btree_node_slab", sizeof(btree_node_t), 0, NULL, NULL, SLAB_CACHE_MAGDEFERRED); |
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83 | } |
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84 | |||
1101 | jermar | 85 | /** Create empty B-tree. |
86 | * |
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87 | * @param t B-tree. |
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88 | */ |
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89 | void btree_create(btree_t *t) |
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90 | { |
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91 | list_initialize(&t->leaf_head); |
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1164 | jermar | 92 | t->root = (btree_node_t *) slab_alloc(btree_node_slab, 0); |
1101 | jermar | 93 | node_initialize(t->root); |
94 | list_append(&t->root->leaf_link, &t->leaf_head); |
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95 | } |
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96 | |||
97 | /** Destroy empty B-tree. */ |
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98 | void btree_destroy(btree_t *t) |
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99 | { |
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100 | ASSERT(!t->root->keys); |
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1164 | jermar | 101 | slab_free(btree_node_slab, t->root); |
1101 | jermar | 102 | } |
103 | |||
104 | /** Insert key-value pair into B-tree. |
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105 | * |
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106 | * @param t B-tree. |
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107 | * @param key Key to be inserted. |
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108 | * @param value Value to be inserted. |
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109 | * @param leaf_node Leaf node where the insertion should begin. |
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110 | */ |
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1177 | jermar | 111 | void btree_insert(btree_t *t, btree_key_t key, void *value, btree_node_t *leaf_node) |
1101 | jermar | 112 | { |
113 | btree_node_t *lnode; |
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114 | |||
115 | ASSERT(value); |
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116 | |||
117 | lnode = leaf_node; |
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118 | if (!lnode) { |
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119 | if (btree_search(t, key, &lnode)) { |
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1221 | decky | 120 | panic("B-tree %p already contains key %d\n", t, key); |
1101 | jermar | 121 | } |
122 | } |
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123 | |||
124 | _btree_insert(t, key, value, NULL, lnode); |
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125 | } |
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126 | |||
127 | /** Recursively insert into B-tree. |
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128 | * |
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129 | * @param t B-tree. |
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130 | * @param key Key to be inserted. |
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131 | * @param value Value to be inserted. |
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132 | * @param rsubtree Right subtree of the inserted key. |
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133 | * @param node Start inserting into this node. |
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134 | */ |
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1177 | jermar | 135 | void _btree_insert(btree_t *t, btree_key_t key, void *value, btree_node_t *rsubtree, btree_node_t *node) |
1101 | jermar | 136 | { |
137 | if (node->keys < BTREE_MAX_KEYS) { |
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138 | /* |
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139 | * Node conatins enough space, the key can be stored immediately. |
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140 | */ |
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1142 | jermar | 141 | node_insert_key_and_rsubtree(node, key, value, rsubtree); |
142 | } else if (try_insert_by_rotation_to_left(node, key, value, rsubtree)) { |
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1136 | jermar | 143 | /* |
144 | * The key-value-rsubtree triplet has been inserted because |
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145 | * some keys could have been moved to the left sibling. |
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146 | */ |
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1142 | jermar | 147 | } else if (try_insert_by_rotation_to_right(node, key, value, rsubtree)) { |
1136 | jermar | 148 | /* |
149 | * The key-value-rsubtree triplet has been inserted because |
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150 | * some keys could have been moved to the right sibling. |
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151 | */ |
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1101 | jermar | 152 | } else { |
153 | btree_node_t *rnode; |
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1177 | jermar | 154 | btree_key_t median; |
1101 | jermar | 155 | |
156 | /* |
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1136 | jermar | 157 | * Node is full and both siblings (if both exist) are full too. |
158 | * Split the node and insert the smallest key from the node containing |
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159 | * bigger keys (i.e. the new node) into its parent. |
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1101 | jermar | 160 | */ |
161 | |||
162 | rnode = node_split(node, key, value, rsubtree, &median); |
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163 | |||
164 | if (LEAF_NODE(node)) { |
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1144 | jermar | 165 | list_prepend(&rnode->leaf_link, &node->leaf_link); |
1101 | jermar | 166 | } |
167 | |||
168 | if (ROOT_NODE(node)) { |
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169 | /* |
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170 | * We split the root node. Create new root. |
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171 | */ |
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1164 | jermar | 172 | t->root = (btree_node_t *) slab_alloc(btree_node_slab, 0); |
1101 | jermar | 173 | node->parent = t->root; |
174 | rnode->parent = t->root; |
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175 | node_initialize(t->root); |
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176 | |||
177 | /* |
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178 | * Left-hand side subtree will be the old root (i.e. node). |
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179 | * Right-hand side subtree will be rnode. |
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180 | */ |
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181 | t->root->subtree[0] = node; |
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182 | |||
183 | t->root->depth = node->depth + 1; |
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184 | } |
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185 | _btree_insert(t, median, NULL, rnode, node->parent); |
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186 | } |
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187 | |||
188 | } |
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189 | |||
1140 | jermar | 190 | /** Remove B-tree node. |
191 | * |
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192 | * @param B-tree. |
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193 | * @param key Key to be removed from the B-tree along with its associated value. |
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194 | * @param leaf_node If not NULL, pointer to the leaf node where the key is found. |
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195 | */ |
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1177 | jermar | 196 | void btree_remove(btree_t *t, btree_key_t key, btree_node_t *leaf_node) |
1101 | jermar | 197 | { |
1140 | jermar | 198 | btree_node_t *lnode; |
199 | |||
200 | lnode = leaf_node; |
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201 | if (!lnode) { |
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202 | if (!btree_search(t, key, &lnode)) { |
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1221 | decky | 203 | panic("B-tree %p does not contain key %d\n", t, key); |
1140 | jermar | 204 | } |
205 | } |
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206 | |||
1142 | jermar | 207 | _btree_remove(t, key, lnode); |
208 | } |
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1140 | jermar | 209 | |
1142 | jermar | 210 | /** Recursively remove B-tree node. |
211 | * |
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212 | * @param B-tree. |
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213 | * @param key Key to be removed from the B-tree along with its associated value. |
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214 | * @param node Node where the key being removed resides. |
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215 | */ |
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1177 | jermar | 216 | void _btree_remove(btree_t *t, btree_key_t key, btree_node_t *node) |
1142 | jermar | 217 | { |
218 | if (ROOT_NODE(node)) { |
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219 | if (node->keys == 1 && node->subtree[0]) { |
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220 | /* |
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221 | * Free the current root and set new root. |
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222 | */ |
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223 | t->root = node->subtree[0]; |
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224 | t->root->parent = NULL; |
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1164 | jermar | 225 | slab_free(btree_node_slab, node); |
1142 | jermar | 226 | } else { |
227 | /* |
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228 | * Remove the key from the root node. |
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229 | * Note that the right subtree is removed because when |
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230 | * combining two nodes, the left-side sibling is preserved |
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231 | * and the right-side sibling is freed. |
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232 | */ |
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233 | node_remove_key_and_rsubtree(node, key); |
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234 | } |
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235 | return; |
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236 | } |
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237 | |||
238 | if (node->keys <= FILL_FACTOR) { |
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239 | /* |
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240 | * If the node is below the fill factor, |
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241 | * try to borrow keys from left or right sibling. |
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242 | */ |
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243 | if (!try_rotation_from_left(node)) |
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244 | try_rotation_from_right(node); |
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245 | } |
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246 | |||
247 | if (node->keys > FILL_FACTOR) { |
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248 | int i; |
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249 | |||
250 | /* |
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251 | * The key can be immediatelly removed. |
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252 | * |
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253 | * Note that the right subtree is removed because when |
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254 | * combining two nodes, the left-side sibling is preserved |
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255 | * and the right-side sibling is freed. |
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256 | */ |
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257 | node_remove_key_and_rsubtree(node, key); |
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258 | for (i = 0; i < node->parent->keys; i++) { |
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259 | if (node->parent->key[i] == key) |
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260 | node->parent->key[i] = node->key[0]; |
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261 | } |
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262 | |||
263 | } else { |
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264 | index_t idx; |
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265 | btree_node_t *rnode, *parent; |
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266 | |||
267 | /* |
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268 | * The node is below the fill factor as well as its left and right sibling. |
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269 | * Resort to combining the node with one of its siblings. |
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270 | * The node which is on the left is preserved and the node on the right is |
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271 | * freed. |
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272 | */ |
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273 | parent = node->parent; |
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274 | node_remove_key_and_rsubtree(node, key); |
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275 | rnode = node_combine(node); |
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276 | if (LEAF_NODE(rnode)) |
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277 | list_remove(&rnode->leaf_link); |
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278 | idx = find_key_by_subtree(parent, rnode, true); |
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279 | ASSERT((int) idx != -1); |
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1164 | jermar | 280 | slab_free(btree_node_slab, rnode); |
1142 | jermar | 281 | _btree_remove(t, parent->key[idx], parent); |
282 | } |
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1101 | jermar | 283 | } |
284 | |||
285 | /** Search key in a B-tree. |
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286 | * |
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287 | * @param t B-tree. |
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288 | * @param key Key to be searched. |
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289 | * @param leaf_node Address where to put pointer to visited leaf node. |
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290 | * |
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291 | * @return Pointer to value or NULL if there is no such key. |
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292 | */ |
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1177 | jermar | 293 | void *btree_search(btree_t *t, btree_key_t key, btree_node_t **leaf_node) |
1101 | jermar | 294 | { |
295 | btree_node_t *cur, *next; |
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296 | |||
297 | /* |
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1134 | jermar | 298 | * Iteratively descend to the leaf that can contain the searched key. |
1101 | jermar | 299 | */ |
300 | for (cur = t->root; cur; cur = next) { |
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1134 | jermar | 301 | |
1101 | jermar | 302 | /* Last iteration will set this with proper leaf node address. */ |
303 | *leaf_node = cur; |
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1134 | jermar | 304 | |
305 | /* |
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306 | * The key can be in the leftmost subtree. |
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307 | * Test it separately. |
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308 | */ |
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309 | if (key < cur->key[0]) { |
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310 | next = cur->subtree[0]; |
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311 | continue; |
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312 | } else { |
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313 | void *val; |
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314 | int i; |
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315 | |||
316 | /* |
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317 | * Now if the key is smaller than cur->key[i] |
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318 | * it can only mean that the value is in cur->subtree[i] |
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319 | * or it is not in the tree at all. |
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320 | */ |
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321 | for (i = 1; i < cur->keys; i++) { |
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322 | if (key < cur->key[i]) { |
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323 | next = cur->subtree[i]; |
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324 | val = cur->value[i - 1]; |
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325 | |||
326 | if (LEAF_NODE(cur)) |
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327 | return key == cur->key[i - 1] ? val : NULL; |
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328 | |||
329 | goto descend; |
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330 | } |
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1101 | jermar | 331 | } |
1134 | jermar | 332 | |
333 | /* |
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334 | * Last possibility is that the key is in the rightmost subtree. |
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335 | */ |
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336 | next = cur->subtree[i]; |
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337 | val = cur->value[i - 1]; |
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338 | if (LEAF_NODE(cur)) |
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339 | return key == cur->key[i - 1] ? val : NULL; |
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1101 | jermar | 340 | } |
1134 | jermar | 341 | descend: |
342 | ; |
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1101 | jermar | 343 | } |
344 | |||
345 | /* |
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1134 | jermar | 346 | * The key was not found in the *leaf_node and is smaller than any of its keys. |
1101 | jermar | 347 | */ |
348 | return NULL; |
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349 | } |
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350 | |||
1150 | jermar | 351 | /** Return pointer to B-tree leaf node's left neighbour. |
1147 | jermar | 352 | * |
353 | * @param t B-tree. |
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1150 | jermar | 354 | * @param node Node whose left neighbour will be returned. |
1147 | jermar | 355 | * |
1150 | jermar | 356 | * @return Left neighbour of the node or NULL if the node does not have the left neighbour. |
1147 | jermar | 357 | */ |
1150 | jermar | 358 | btree_node_t *btree_leaf_node_left_neighbour(btree_t *t, btree_node_t *node) |
1147 | jermar | 359 | { |
360 | ASSERT(LEAF_NODE(node)); |
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361 | if (node->leaf_link.prev != &t->leaf_head) |
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362 | return list_get_instance(node->leaf_link.prev, btree_node_t, leaf_link); |
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363 | else |
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364 | return NULL; |
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365 | } |
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366 | |||
1150 | jermar | 367 | /** Return pointer to B-tree leaf node's right neighbour. |
1147 | jermar | 368 | * |
369 | * @param t B-tree. |
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1150 | jermar | 370 | * @param node Node whose right neighbour will be returned. |
1147 | jermar | 371 | * |
1150 | jermar | 372 | * @return Right neighbour of the node or NULL if the node does not have the right neighbour. |
1147 | jermar | 373 | */ |
1150 | jermar | 374 | btree_node_t *btree_leaf_node_right_neighbour(btree_t *t, btree_node_t *node) |
1147 | jermar | 375 | { |
376 | ASSERT(LEAF_NODE(node)); |
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377 | if (node->leaf_link.next != &t->leaf_head) |
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378 | return list_get_instance(node->leaf_link.next, btree_node_t, leaf_link); |
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379 | else |
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380 | return NULL; |
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381 | } |
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382 | |||
1101 | jermar | 383 | /** Initialize B-tree node. |
384 | * |
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385 | * @param node B-tree node. |
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386 | */ |
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387 | void node_initialize(btree_node_t *node) |
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388 | { |
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389 | int i; |
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390 | |||
391 | node->keys = 0; |
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392 | |||
393 | /* Clean also space for the extra key. */ |
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394 | for (i = 0; i < BTREE_MAX_KEYS + 1; i++) { |
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395 | node->key[i] = 0; |
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396 | node->value[i] = NULL; |
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397 | node->subtree[i] = NULL; |
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398 | } |
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399 | node->subtree[i] = NULL; |
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400 | |||
401 | node->parent = NULL; |
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402 | |||
403 | link_initialize(&node->leaf_link); |
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404 | |||
405 | link_initialize(&node->bfs_link); |
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406 | node->depth = 0; |
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407 | } |
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408 | |||
1136 | jermar | 409 | /** Insert key-value-lsubtree triplet into B-tree node. |
1101 | jermar | 410 | * |
411 | * It is actually possible to have more keys than BTREE_MAX_KEYS. |
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1136 | jermar | 412 | * This feature is used during insert by right rotation. |
413 | * |
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414 | * @param node B-tree node into wich the new key is to be inserted. |
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415 | * @param key The key to be inserted. |
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416 | * @param value Pointer to value to be inserted. |
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417 | * @param lsubtree Pointer to the left subtree. |
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418 | */ |
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1177 | jermar | 419 | void node_insert_key_and_lsubtree(btree_node_t *node, btree_key_t key, void *value, btree_node_t *lsubtree) |
1136 | jermar | 420 | { |
421 | int i; |
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422 | |||
423 | for (i = 0; i < node->keys; i++) { |
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424 | if (key < node->key[i]) { |
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425 | int j; |
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426 | |||
427 | for (j = node->keys; j > i; j--) { |
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428 | node->key[j] = node->key[j - 1]; |
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429 | node->value[j] = node->value[j - 1]; |
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430 | node->subtree[j + 1] = node->subtree[j]; |
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431 | } |
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432 | node->subtree[j + 1] = node->subtree[j]; |
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433 | break; |
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434 | } |
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435 | } |
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436 | node->key[i] = key; |
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437 | node->value[i] = value; |
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438 | node->subtree[i] = lsubtree; |
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439 | |||
440 | node->keys++; |
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441 | } |
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442 | |||
443 | /** Insert key-value-rsubtree triplet into B-tree node. |
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444 | * |
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445 | * It is actually possible to have more keys than BTREE_MAX_KEYS. |
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1101 | jermar | 446 | * This feature is used during splitting the node when the |
1136 | jermar | 447 | * number of keys is BTREE_MAX_KEYS + 1. Insert by left rotation |
448 | * also makes use of this feature. |
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1101 | jermar | 449 | * |
450 | * @param node B-tree node into wich the new key is to be inserted. |
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451 | * @param key The key to be inserted. |
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452 | * @param value Pointer to value to be inserted. |
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453 | * @param rsubtree Pointer to the right subtree. |
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454 | */ |
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1177 | jermar | 455 | void node_insert_key_and_rsubtree(btree_node_t *node, btree_key_t key, void *value, btree_node_t *rsubtree) |
1101 | jermar | 456 | { |
457 | int i; |
||
458 | |||
459 | for (i = 0; i < node->keys; i++) { |
||
460 | if (key < node->key[i]) { |
||
461 | int j; |
||
462 | |||
463 | for (j = node->keys; j > i; j--) { |
||
464 | node->key[j] = node->key[j - 1]; |
||
465 | node->value[j] = node->value[j - 1]; |
||
466 | node->subtree[j + 1] = node->subtree[j]; |
||
467 | } |
||
468 | break; |
||
469 | } |
||
470 | } |
||
471 | node->key[i] = key; |
||
472 | node->value[i] = value; |
||
473 | node->subtree[i + 1] = rsubtree; |
||
474 | |||
475 | node->keys++; |
||
476 | } |
||
477 | |||
1144 | jermar | 478 | /** Remove key and its left subtree pointer from B-tree node. |
479 | * |
||
480 | * Remove the key and eliminate gaps in node->key array. |
||
481 | * Note that the value pointer and the left subtree pointer |
||
482 | * is removed from the node as well. |
||
483 | * |
||
484 | * @param node B-tree node. |
||
485 | * @param key Key to be removed. |
||
486 | */ |
||
1177 | jermar | 487 | void node_remove_key_and_lsubtree(btree_node_t *node, btree_key_t key) |
1144 | jermar | 488 | { |
489 | int i, j; |
||
490 | |||
491 | for (i = 0; i < node->keys; i++) { |
||
492 | if (key == node->key[i]) { |
||
493 | for (j = i + 1; j < node->keys; j++) { |
||
494 | node->key[j - 1] = node->key[j]; |
||
495 | node->value[j - 1] = node->value[j]; |
||
496 | node->subtree[j - 1] = node->subtree[j]; |
||
497 | } |
||
498 | node->subtree[j - 1] = node->subtree[j]; |
||
499 | node->keys--; |
||
500 | return; |
||
501 | } |
||
502 | } |
||
1221 | decky | 503 | panic("node %p does not contain key %d\n", node, key); |
1144 | jermar | 504 | } |
505 | |||
506 | /** Remove key and its right subtree pointer from B-tree node. |
||
507 | * |
||
508 | * Remove the key and eliminate gaps in node->key array. |
||
509 | * Note that the value pointer and the right subtree pointer |
||
510 | * is removed from the node as well. |
||
511 | * |
||
512 | * @param node B-tree node. |
||
513 | * @param key Key to be removed. |
||
514 | */ |
||
1177 | jermar | 515 | void node_remove_key_and_rsubtree(btree_node_t *node, btree_key_t key) |
1144 | jermar | 516 | { |
517 | int i, j; |
||
518 | |||
519 | for (i = 0; i < node->keys; i++) { |
||
520 | if (key == node->key[i]) { |
||
521 | for (j = i + 1; j < node->keys; j++) { |
||
522 | node->key[j - 1] = node->key[j]; |
||
523 | node->value[j - 1] = node->value[j]; |
||
524 | node->subtree[j] = node->subtree[j + 1]; |
||
525 | } |
||
526 | node->keys--; |
||
527 | return; |
||
528 | } |
||
529 | } |
||
1221 | decky | 530 | panic("node %p does not contain key %d\n", node, key); |
1144 | jermar | 531 | } |
532 | |||
1134 | jermar | 533 | /** Split full B-tree node and insert new key-value-right-subtree triplet. |
1101 | jermar | 534 | * |
535 | * This function will split a node and return pointer to a newly created |
||
1134 | jermar | 536 | * node containing keys greater than or equal to the greater of medians |
537 | * (or median) of the old keys and the newly added key. It will also write |
||
538 | * the median key to a memory address supplied by the caller. |
||
1101 | jermar | 539 | * |
1134 | jermar | 540 | * If the node being split is an index node, the median will not be |
541 | * included in the new node. If the node is a leaf node, |
||
542 | * the median will be copied there. |
||
1101 | jermar | 543 | * |
544 | * @param node B-tree node wich is going to be split. |
||
545 | * @param key The key to be inserted. |
||
546 | * @param value Pointer to the value to be inserted. |
||
547 | * @param rsubtree Pointer to the right subtree of the key being added. |
||
548 | * @param median Address in memory, where the median key will be stored. |
||
549 | * |
||
550 | * @return Newly created right sibling of node. |
||
551 | */ |
||
1177 | jermar | 552 | btree_node_t *node_split(btree_node_t *node, btree_key_t key, void *value, btree_node_t *rsubtree, btree_key_t *median) |
1101 | jermar | 553 | { |
554 | btree_node_t *rnode; |
||
555 | int i, j; |
||
556 | |||
557 | ASSERT(median); |
||
558 | ASSERT(node->keys == BTREE_MAX_KEYS); |
||
1136 | jermar | 559 | |
1101 | jermar | 560 | /* |
561 | * Use the extra space to store the extra node. |
||
562 | */ |
||
1142 | jermar | 563 | node_insert_key_and_rsubtree(node, key, value, rsubtree); |
1101 | jermar | 564 | |
565 | /* |
||
566 | * Compute median of keys. |
||
567 | */ |
||
1134 | jermar | 568 | *median = MEDIAN_HIGH(node); |
1101 | jermar | 569 | |
1134 | jermar | 570 | /* |
571 | * Allocate and initialize new right sibling. |
||
572 | */ |
||
1164 | jermar | 573 | rnode = (btree_node_t *) slab_alloc(btree_node_slab, 0); |
1101 | jermar | 574 | node_initialize(rnode); |
575 | rnode->parent = node->parent; |
||
576 | rnode->depth = node->depth; |
||
577 | |||
578 | /* |
||
579 | * Copy big keys, values and subtree pointers to the new right sibling. |
||
1134 | jermar | 580 | * If this is an index node, do not copy the median. |
1101 | jermar | 581 | */ |
1134 | jermar | 582 | i = (int) INDEX_NODE(node); |
583 | for (i += MEDIAN_HIGH_INDEX(node), j = 0; i < node->keys; i++, j++) { |
||
1101 | jermar | 584 | rnode->key[j] = node->key[i]; |
585 | rnode->value[j] = node->value[i]; |
||
586 | rnode->subtree[j] = node->subtree[i]; |
||
587 | |||
588 | /* |
||
589 | * Fix parent links in subtrees. |
||
590 | */ |
||
591 | if (rnode->subtree[j]) |
||
592 | rnode->subtree[j]->parent = rnode; |
||
593 | |||
594 | } |
||
595 | rnode->subtree[j] = node->subtree[i]; |
||
596 | if (rnode->subtree[j]) |
||
597 | rnode->subtree[j]->parent = rnode; |
||
1134 | jermar | 598 | |
599 | rnode->keys = j; /* Set number of keys of the new node. */ |
||
600 | node->keys /= 2; /* Shrink the old node. */ |
||
1101 | jermar | 601 | |
602 | return rnode; |
||
603 | } |
||
604 | |||
1142 | jermar | 605 | /** Combine node with any of its siblings. |
606 | * |
||
607 | * The siblings are required to be below the fill factor. |
||
608 | * |
||
609 | * @param node Node to combine with one of its siblings. |
||
610 | * |
||
611 | * @return Pointer to the rightmost of the two nodes. |
||
612 | */ |
||
613 | btree_node_t *node_combine(btree_node_t *node) |
||
614 | { |
||
615 | index_t idx; |
||
616 | btree_node_t *rnode; |
||
617 | int i; |
||
618 | |||
619 | ASSERT(!ROOT_NODE(node)); |
||
620 | |||
621 | idx = find_key_by_subtree(node->parent, node, false); |
||
622 | if (idx == node->parent->keys) { |
||
623 | /* |
||
624 | * Rightmost subtree of its parent, combine with the left sibling. |
||
625 | */ |
||
626 | idx--; |
||
627 | rnode = node; |
||
628 | node = node->parent->subtree[idx]; |
||
629 | } else { |
||
630 | rnode = node->parent->subtree[idx + 1]; |
||
631 | } |
||
632 | |||
633 | /* Index nodes need to insert parent node key in between left and right node. */ |
||
634 | if (INDEX_NODE(node)) |
||
635 | node->key[node->keys++] = node->parent->key[idx]; |
||
636 | |||
637 | /* Copy the key-value-subtree triplets from the right node. */ |
||
638 | for (i = 0; i < rnode->keys; i++) { |
||
639 | node->key[node->keys + i] = rnode->key[i]; |
||
640 | node->value[node->keys + i] = rnode->value[i]; |
||
641 | if (INDEX_NODE(node)) { |
||
642 | node->subtree[node->keys + i] = rnode->subtree[i]; |
||
643 | rnode->subtree[i]->parent = node; |
||
644 | } |
||
645 | } |
||
646 | if (INDEX_NODE(node)) { |
||
647 | node->subtree[node->keys + i] = rnode->subtree[i]; |
||
648 | rnode->subtree[i]->parent = node; |
||
649 | } |
||
650 | |||
651 | node->keys += rnode->keys; |
||
652 | |||
653 | return rnode; |
||
654 | } |
||
655 | |||
1136 | jermar | 656 | /** Find key by its left or right subtree. |
657 | * |
||
658 | * @param node B-tree node. |
||
659 | * @param subtree Left or right subtree of a key found in node. |
||
660 | * @param right If true, subtree is a right subtree. If false, subtree is a left subtree. |
||
661 | * |
||
662 | * @return Index of the key associated with the subtree. |
||
663 | */ |
||
664 | index_t find_key_by_subtree(btree_node_t *node, btree_node_t *subtree, bool right) |
||
665 | { |
||
666 | int i; |
||
667 | |||
668 | for (i = 0; i < node->keys + 1; i++) { |
||
669 | if (subtree == node->subtree[i]) |
||
670 | return i - (int) (right != false); |
||
671 | } |
||
1221 | decky | 672 | panic("node %p does not contain subtree %p\n", node, subtree); |
1136 | jermar | 673 | } |
674 | |||
1142 | jermar | 675 | /** Rotate one key-value-rsubtree triplet from the left sibling to the right sibling. |
676 | * |
||
677 | * The biggest key and its value and right subtree is rotated from the left node |
||
678 | * to the right. If the node is an index node, than the parent node key belonging to |
||
679 | * the left node takes part in the rotation. |
||
680 | * |
||
681 | * @param lnode Left sibling. |
||
682 | * @param rnode Right sibling. |
||
683 | * @param idx Index of the parent node key that is taking part in the rotation. |
||
684 | */ |
||
685 | void rotate_from_left(btree_node_t *lnode, btree_node_t *rnode, index_t idx) |
||
686 | { |
||
1177 | jermar | 687 | btree_key_t key; |
1142 | jermar | 688 | |
689 | key = lnode->key[lnode->keys - 1]; |
||
690 | |||
691 | if (LEAF_NODE(lnode)) { |
||
692 | void *value; |
||
693 | |||
694 | value = lnode->value[lnode->keys - 1]; |
||
695 | node_remove_key_and_rsubtree(lnode, key); |
||
696 | node_insert_key_and_lsubtree(rnode, key, value, NULL); |
||
697 | lnode->parent->key[idx] = key; |
||
698 | } else { |
||
699 | btree_node_t *rsubtree; |
||
700 | |||
701 | rsubtree = lnode->subtree[lnode->keys]; |
||
702 | node_remove_key_and_rsubtree(lnode, key); |
||
703 | node_insert_key_and_lsubtree(rnode, lnode->parent->key[idx], NULL, rsubtree); |
||
704 | lnode->parent->key[idx] = key; |
||
705 | |||
706 | /* Fix parent link of the reconnected right subtree. */ |
||
707 | rsubtree->parent = rnode; |
||
708 | } |
||
709 | |||
710 | } |
||
711 | |||
712 | /** Rotate one key-value-lsubtree triplet from the right sibling to the left sibling. |
||
713 | * |
||
714 | * The smallest key and its value and left subtree is rotated from the right node |
||
715 | * to the left. If the node is an index node, than the parent node key belonging to |
||
716 | * the right node takes part in the rotation. |
||
717 | * |
||
718 | * @param lnode Left sibling. |
||
719 | * @param rnode Right sibling. |
||
720 | * @param idx Index of the parent node key that is taking part in the rotation. |
||
721 | */ |
||
722 | void rotate_from_right(btree_node_t *lnode, btree_node_t *rnode, index_t idx) |
||
723 | { |
||
1177 | jermar | 724 | btree_key_t key; |
1142 | jermar | 725 | |
726 | key = rnode->key[0]; |
||
727 | |||
728 | if (LEAF_NODE(rnode)) { |
||
729 | void *value; |
||
730 | |||
731 | value = rnode->value[0]; |
||
732 | node_remove_key_and_lsubtree(rnode, key); |
||
733 | node_insert_key_and_rsubtree(lnode, key, value, NULL); |
||
734 | rnode->parent->key[idx] = rnode->key[0]; |
||
735 | } else { |
||
736 | btree_node_t *lsubtree; |
||
737 | |||
738 | lsubtree = rnode->subtree[0]; |
||
739 | node_remove_key_and_lsubtree(rnode, key); |
||
740 | node_insert_key_and_rsubtree(lnode, rnode->parent->key[idx], NULL, lsubtree); |
||
741 | rnode->parent->key[idx] = key; |
||
742 | |||
743 | /* Fix parent link of the reconnected left subtree. */ |
||
744 | lsubtree->parent = lnode; |
||
745 | } |
||
746 | |||
747 | } |
||
748 | |||
1136 | jermar | 749 | /** Insert key-value-rsubtree triplet and rotate the node to the left, if this operation can be done. |
750 | * |
||
751 | * Left sibling of the node (if it exists) is checked for free space. |
||
752 | * If there is free space, the key is inserted and the smallest key of |
||
753 | * the node is moved there. The index node which is the parent of both |
||
754 | * nodes is fixed. |
||
755 | * |
||
756 | * @param node B-tree node. |
||
757 | * @param inskey Key to be inserted. |
||
758 | * @param insvalue Value to be inserted. |
||
759 | * @param rsubtree Right subtree of inskey. |
||
760 | * |
||
761 | * @return True if the rotation was performed, false otherwise. |
||
762 | */ |
||
1177 | jermar | 763 | bool try_insert_by_rotation_to_left(btree_node_t *node, btree_key_t inskey, void *insvalue, btree_node_t *rsubtree) |
1136 | jermar | 764 | { |
765 | index_t idx; |
||
766 | btree_node_t *lnode; |
||
767 | |||
768 | /* |
||
769 | * If this is root node, the rotation can not be done. |
||
770 | */ |
||
771 | if (ROOT_NODE(node)) |
||
772 | return false; |
||
773 | |||
774 | idx = find_key_by_subtree(node->parent, node, true); |
||
775 | if ((int) idx == -1) { |
||
776 | /* |
||
777 | * If this node is the leftmost subtree of its parent, |
||
778 | * the rotation can not be done. |
||
779 | */ |
||
780 | return false; |
||
781 | } |
||
782 | |||
783 | lnode = node->parent->subtree[idx]; |
||
784 | if (lnode->keys < BTREE_MAX_KEYS) { |
||
785 | /* |
||
786 | * The rotaion can be done. The left sibling has free space. |
||
787 | */ |
||
1142 | jermar | 788 | node_insert_key_and_rsubtree(node, inskey, insvalue, rsubtree); |
789 | rotate_from_right(lnode, node, idx); |
||
1136 | jermar | 790 | return true; |
791 | } |
||
792 | |||
793 | return false; |
||
794 | } |
||
795 | |||
796 | /** Insert key-value-rsubtree triplet and rotate the node to the right, if this operation can be done. |
||
797 | * |
||
798 | * Right sibling of the node (if it exists) is checked for free space. |
||
799 | * If there is free space, the key is inserted and the biggest key of |
||
800 | * the node is moved there. The index node which is the parent of both |
||
801 | * nodes is fixed. |
||
802 | * |
||
803 | * @param node B-tree node. |
||
804 | * @param inskey Key to be inserted. |
||
805 | * @param insvalue Value to be inserted. |
||
806 | * @param rsubtree Right subtree of inskey. |
||
807 | * |
||
808 | * @return True if the rotation was performed, false otherwise. |
||
809 | */ |
||
1177 | jermar | 810 | bool try_insert_by_rotation_to_right(btree_node_t *node, btree_key_t inskey, void *insvalue, btree_node_t *rsubtree) |
1136 | jermar | 811 | { |
812 | index_t idx; |
||
813 | btree_node_t *rnode; |
||
814 | |||
815 | /* |
||
816 | * If this is root node, the rotation can not be done. |
||
817 | */ |
||
818 | if (ROOT_NODE(node)) |
||
819 | return false; |
||
820 | |||
821 | idx = find_key_by_subtree(node->parent, node, false); |
||
822 | if (idx == node->parent->keys) { |
||
823 | /* |
||
824 | * If this node is the rightmost subtree of its parent, |
||
825 | * the rotation can not be done. |
||
826 | */ |
||
827 | return false; |
||
828 | } |
||
829 | |||
830 | rnode = node->parent->subtree[idx + 1]; |
||
831 | if (rnode->keys < BTREE_MAX_KEYS) { |
||
832 | /* |
||
833 | * The rotaion can be done. The right sibling has free space. |
||
834 | */ |
||
1142 | jermar | 835 | node_insert_key_and_rsubtree(node, inskey, insvalue, rsubtree); |
836 | rotate_from_left(node, rnode, idx); |
||
837 | return true; |
||
838 | } |
||
1136 | jermar | 839 | |
1142 | jermar | 840 | return false; |
841 | } |
||
1136 | jermar | 842 | |
1142 | jermar | 843 | /** Rotate in a key from the left sibling or from the index node, if this operation can be done. |
844 | * |
||
845 | * @param rnode Node into which to add key from its left sibling or from the index node. |
||
846 | * |
||
847 | * @return True if the rotation was performed, false otherwise. |
||
848 | */ |
||
849 | bool try_rotation_from_left(btree_node_t *rnode) |
||
850 | { |
||
851 | index_t idx; |
||
852 | btree_node_t *lnode; |
||
1136 | jermar | 853 | |
1142 | jermar | 854 | /* |
855 | * If this is root node, the rotation can not be done. |
||
856 | */ |
||
857 | if (ROOT_NODE(rnode)) |
||
858 | return false; |
||
859 | |||
860 | idx = find_key_by_subtree(rnode->parent, rnode, true); |
||
861 | if ((int) idx == -1) { |
||
862 | /* |
||
863 | * If this node is the leftmost subtree of its parent, |
||
864 | * the rotation can not be done. |
||
865 | */ |
||
866 | return false; |
||
867 | } |
||
868 | |||
869 | lnode = rnode->parent->subtree[idx]; |
||
870 | if (lnode->keys > FILL_FACTOR) { |
||
871 | rotate_from_left(lnode, rnode, idx); |
||
1136 | jermar | 872 | return true; |
873 | } |
||
1142 | jermar | 874 | |
875 | return false; |
||
876 | } |
||
1136 | jermar | 877 | |
1142 | jermar | 878 | /** Rotate in a key from the right sibling or from the index node, if this operation can be done. |
879 | * |
||
880 | * @param rnode Node into which to add key from its right sibling or from the index node. |
||
881 | * |
||
882 | * @return True if the rotation was performed, false otherwise. |
||
883 | */ |
||
884 | bool try_rotation_from_right(btree_node_t *lnode) |
||
885 | { |
||
886 | index_t idx; |
||
887 | btree_node_t *rnode; |
||
888 | |||
889 | /* |
||
890 | * If this is root node, the rotation can not be done. |
||
891 | */ |
||
892 | if (ROOT_NODE(lnode)) |
||
893 | return false; |
||
894 | |||
895 | idx = find_key_by_subtree(lnode->parent, lnode, false); |
||
896 | if (idx == lnode->parent->keys) { |
||
897 | /* |
||
898 | * If this node is the rightmost subtree of its parent, |
||
899 | * the rotation can not be done. |
||
900 | */ |
||
901 | return false; |
||
902 | } |
||
903 | |||
904 | rnode = lnode->parent->subtree[idx + 1]; |
||
905 | if (rnode->keys > FILL_FACTOR) { |
||
906 | rotate_from_right(lnode, rnode, idx); |
||
907 | return true; |
||
908 | } |
||
909 | |||
1136 | jermar | 910 | return false; |
911 | } |
||
912 | |||
1101 | jermar | 913 | /** Print B-tree. |
914 | * |
||
915 | * @param t Print out B-tree. |
||
916 | */ |
||
917 | void btree_print(btree_t *t) |
||
918 | { |
||
919 | int i, depth = t->root->depth; |
||
1144 | jermar | 920 | link_t head, *cur; |
921 | |||
922 | printf("Printing B-tree:\n"); |
||
1101 | jermar | 923 | list_initialize(&head); |
924 | list_append(&t->root->bfs_link, &head); |
||
925 | |||
926 | /* |
||
927 | * Use BFS search to print out the tree. |
||
928 | * Levels are distinguished from one another by node->depth. |
||
929 | */ |
||
930 | while (!list_empty(&head)) { |
||
931 | link_t *hlp; |
||
932 | btree_node_t *node; |
||
933 | |||
934 | hlp = head.next; |
||
935 | ASSERT(hlp != &head); |
||
936 | node = list_get_instance(hlp, btree_node_t, bfs_link); |
||
937 | list_remove(hlp); |
||
938 | |||
939 | ASSERT(node); |
||
940 | |||
941 | if (node->depth != depth) { |
||
942 | printf("\n"); |
||
943 | depth = node->depth; |
||
944 | } |
||
945 | |||
946 | printf("("); |
||
947 | for (i = 0; i < node->keys; i++) { |
||
1196 | cejka | 948 | printf("%lld%s", node->key[i], i < node->keys - 1 ? "," : ""); |
1101 | jermar | 949 | if (node->depth && node->subtree[i]) { |
950 | list_append(&node->subtree[i]->bfs_link, &head); |
||
951 | } |
||
952 | } |
||
953 | if (node->depth && node->subtree[i]) { |
||
954 | list_append(&node->subtree[i]->bfs_link, &head); |
||
955 | } |
||
956 | printf(")"); |
||
957 | } |
||
958 | printf("\n"); |
||
1144 | jermar | 959 | |
960 | printf("Printing list of leaves:\n"); |
||
961 | for (cur = t->leaf_head.next; cur != &t->leaf_head; cur = cur->next) { |
||
962 | btree_node_t *node; |
||
963 | |||
964 | node = list_get_instance(cur, btree_node_t, leaf_link); |
||
965 | |||
966 | ASSERT(node); |
||
967 | |||
968 | printf("("); |
||
969 | for (i = 0; i < node->keys; i++) |
||
1196 | cejka | 970 | printf("%lld%s", node->key[i], i < node->keys - 1 ? "," : ""); |
1144 | jermar | 971 | printf(")"); |
972 | } |
||
973 | printf("\n"); |
||
1101 | jermar | 974 | } |