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Line 111... | Line 111... | ||
111 | for (i = 0; i < len; i++) { |
111 | for (i = 0; i < len; i++) { |
112 | if (!(dest[i] = src[i])) |
112 | if (!(dest[i] = src[i])) |
113 | return; |
113 | return; |
114 | } |
114 | } |
115 | } |
115 | } |
- | 116 | ||
- | 117 | /** Convert ascii representation to __native |
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- | 118 | * |
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- | 119 | * Supports 0x for hexa & 0 for octal notation. |
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- | 120 | * Does not check for overflows, does not support negative numbers |
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- | 121 | * |
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- | 122 | * @param text Textual representation of number |
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- | 123 | * @return Converted number or 0 if no valid number ofund |
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- | 124 | */ |
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- | 125 | __native atoi(const char *text) |
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- | 126 | { |
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- | 127 | int base = 10; |
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- | 128 | __native result = 0; |
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- | 129 | ||
- | 130 | if (text[0] == '0' && text[1] == 'x') { |
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- | 131 | base = 16; |
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- | 132 | text += 2; |
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- | 133 | } else if (text[0] == '0') |
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- | 134 | base = 8; |
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- | 135 | ||
- | 136 | while (*text) { |
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- | 137 | result *= base; |
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- | 138 | if (base != 16 && *text >= 'A' && *text <= 'F') |
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- | 139 | break; |
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- | 140 | if (base == 8 && *text >='8') |
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- | 141 | break; |
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- | 142 | ||
- | 143 | if (*text >= '0' && *text <= '9') |
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- | 144 | result += *text - '0'; |
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- | 145 | else if (*text >= 'A' && *text <= 'F') |
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- | 146 | result += *text - 'A' + 10; |
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- | 147 | else |
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- | 148 | break; |
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- | 149 | text++; |
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- | 150 | } |
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- | 151 | ||
- | 152 | return result; |
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- | 153 | } |